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grep: Remove trailing newline before trying to match RE

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This unbreaks the "$" operator
and some uses of grep with other REs
(e.g. 'grep . TODO' to remove empty lines).
This commit is contained in:
Robert Ransom 2012-05-22 00:05:03 +00:00
parent 8ed28e50e4
commit e6238dda31
1 changed files with 5 additions and 2 deletions
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7
grep.c
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@ -3,6 +3,7 @@
#include <stdbool.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <unistd.h>
#include "text.h"
#include "util.h"
@ -70,9 +71,11 @@ grep(FILE *fp, const char *str, regex_t *preg)
{
char *buf = NULL;
long n, c = 0;
size_t size = 0;
size_t size = 0, len;
for(n = 1; afgets(&buf, &size, fp); n++) {
if(buf[(len = strlen(buf))-1] == '\n')
buf[--len] = '\0';
if(regexec(preg, buf, 0, NULL, 0) ^ vflag)
continue;
switch(mode) {
@ -89,7 +92,7 @@ grep(FILE *fp, const char *str, regex_t *preg)
printf("%s:", str);
if(mode == 'n')
printf("%ld:", n);
fputs(buf, stdout);
printf("%s\n", buf);
break;
}
match = true;