test: eprintf in usage
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5
test.c
5
test.c
@ -114,7 +114,6 @@ usage(void)
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{
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const char *ket = (*argv0 == '[') ? " ]" : "";
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fprintf(stderr, "usage: %s string%s\n"
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" %s [!] [-bcdefghLnprSstuwxz] string%s\n", argv0, ket, argv0, ket);
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exit(EXIT_FAILURE);
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eprintf("usage: %s string%s\n"
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" %s [!] [-bcdefghLnprSstuwxz] string%s\n", argv0, ket, argv0, ket);
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}
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