75 lines
2.3 KiB
Coq
75 lines
2.3 KiB
Coq
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Require Import Nat.
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Require Import PeanoNat.
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Require Import List.
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Import ListNotations.
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Definition subsequence (l s : list nat) :=
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exists (l1: list nat) (l2 : list (list nat)),
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length s = length l2
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/\ l = l1 ++ flat_map (fun e => (fst e) :: (snd e)) (combine s l2).
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Definition subsequence2 (l s : list nat) :=
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exists (t: list bool),
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length t = length l /\ s = map snd (filter fst (combine t l)).
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Theorem subsequence_eq_def : forall l s, subsequence l s <-> subsequence2 l s.
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Proof.
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intro l. induction l.
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(* first part of the induction *)
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intro s. unfold subsequence. unfold subsequence2.
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split. exists nil. split. reflexivity. simpl.
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destruct H. destruct H. destruct H.
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assert (x = nil). destruct x. reflexivity. simpl in H0.
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apply nil_cons in H0. contradiction H0. rewrite H1 in H0.
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simpl in H0. assert (combine s x0 = nil).
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destruct (combine s x0). reflexivity. simpl in H0.
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apply nil_cons in H0. contradiction H0.
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destruct x0. destruct s. reflexivity. simpl in H.
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apply PeanoNat.Nat.neq_succ_0 in H. contradiction H.
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destruct s. reflexivity. simpl in H2.
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symmetry in H2. apply nil_cons in H2. contradiction H2.
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exists nil. exists nil. destruct s. simpl. easy.
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destruct H. destruct H.
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assert (x = nil). destruct x. reflexivity. simpl in H.
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apply PeanoNat.Nat.neq_succ_0 in H. contradiction H.
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rewrite H1 in H0. simpl in H0.
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symmetry in H0. apply nil_cons in H0. contradiction H0.
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(* second part of the induction *)
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intro s. destruct s. unfold subsequence. unfold subsequence2. split.
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exists (repeat false (S (length l))). rewrite repeat_length.
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split. easy. simpl.
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assert (forall u,
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(nil: list nat)
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= map snd (filter fst (combine (repeat false (length u)) u))).
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intro u. induction u. reflexivity. simpl. assumption. apply H0.
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exists (a::l). exists (nil). simpl. split; try rewrite app_nil_r; reflexivity.
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destruct H. destruct H. destruct H.
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assert (x0 = nil). symmetry in H. apply length_zero_iff_nil in H.
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assumption. rewrite H1 in H0. simpl in H0.
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Example test1: subsequence [1;2;3;4;5] [1;3;5].
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Proof.
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unfold subsequence.
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exists [].
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exists [[2];[4];[]]. simpl. easy.
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Qed.
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Example test2: subsequence [1;2;3;4;5] [2;4].
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Proof.
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unfold subsequence.
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exists [1].
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exists [[3];[5]]. simpl. easy.
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Qed.
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