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We cannot use eprintf() without first initializing argv0

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sin 2014-10-16 11:40:57 +01:00
parent 04a30829a2
commit faf12794db
1 changed files with 11 additions and 7 deletions
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18
last.c
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@ -12,11 +12,10 @@
#include "config.h"
#include "util.h"
void
static void
usage(void)
{
fputs("last [user]\n", stderr);
exit(1);
eprintf("usage: %s [user]\n", argv0);
}
int
@ -27,18 +26,23 @@ main(int argc, char **argv)
char *user, *file, *prog;
time_t t;
ARGBEGIN {
default:
usage();
} ARGEND;
switch (argc) {
case 1:
case 0:
user = NULL;
break;
case 2:
user = argv[1];
case 1:
user = argv[0];
break;
default:
usage();
}
prog = basename(argv[0]);
prog = basename(argv0);
file = (!strcmp(prog, "last")) ? WTMP_PATH : BTMP_PATH;
if ((fp = fopen(file, "r")) == NULL)
eprintf("fopen %s:", file);