midfavila/ubase
1
0
Fork 0
Code Issues Pull Requests Projects Releases 1 Wiki Activity

We cannot use eprintf() without first initializing argv0

Browse Source
This commit is contained in:
sin 2014-10-16 11:40:57 +01:00
parent 04a30829a2
commit faf12794db
1 changed files with 11 additions and 7 deletions
Show Stats Download Patch File Download Diff File Expand all files Collapse all files

18
last.c
View File

@ -12,11 +12,10 @@
#include "config.h" #include "config.h"
#include "util.h" #include "util.h"
void static void
usage(void) usage(void)
{ {
fputs("last [user]\n", stderr); eprintf("usage: %s [user]\n", argv0);
exit(1);
} }
int int
@ -27,18 +26,23 @@ main(int argc, char **argv)
char *user, *file, *prog; char *user, *file, *prog;
time_t t; time_t t;
ARGBEGIN {
default:
usage();
} ARGEND;
switch (argc) { switch (argc) {
case 1: case 0:
user = NULL; user = NULL;
break; break;
case 2: case 1:
user = argv[1]; user = argv[0];
break; break;
default: default:
usage(); usage();
} }
prog = basename(argv[0]); prog = basename(argv0);
file = (!strcmp(prog, "last")) ? WTMP_PATH : BTMP_PATH; file = (!strcmp(prog, "last")) ? WTMP_PATH : BTMP_PATH;
if ((fp = fopen(file, "r")) == NULL) if ((fp = fopen(file, "r")) == NULL)
eprintf("fopen %s:", file); eprintf("fopen %s:", file);