printf: support escaping '%' with '%%'. See printf(1p) EXAMPLES section.

master
pranomostro 7 years ago committed by sin
parent 11d8e91042
commit 229d7cc89a

@ -103,8 +103,10 @@ main(int argc, char *argv[])
arg = "";
cooldown = 1;
}
} else
} else {
putchar('%');
continue;
}
switch (format[i]) {
case 'b':

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