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patch 8.2.5057: using gettimeofday() for timeout is very inefficient

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Problem:    Using gettimeofday() for timeout is very inefficient.
Solution:   Set a platform dependent timer. (Paul Ollis, closes #10505)
This commit is contained in:
Paul Ollis
2022-06-05 16:55:54 +01:00
committed by Bram Moolenaar
parent 1d97db3d98
commit 6574577cac
29 changed files with 811 additions and 242 deletions
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4
src/proto/regexp.pro
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@@ -1,4 +1,6 @@
/* regexp.c */
void init_regexp_timeout(long msec);
void disable_regexp_timeout(void);
int re_multiline(regprog_T *prog);
char_u *skip_regexp(char_u *startp, int delim, int magic);
char_u *skip_regexp_err(char_u *startp, int delim, int magic);
@@ -18,5 +20,5 @@ int regprog_in_use(regprog_T *prog);
int vim_regexec_prog(regprog_T **prog, int ignore_case, char_u *line, colnr_T col);
int vim_regexec(regmatch_T *rmp, char_u *line, colnr_T col);
int vim_regexec_nl(regmatch_T *rmp, char_u *line, colnr_T col);
long vim_regexec_multi(regmmatch_T *rmp, win_T *win, buf_T *buf, linenr_T lnum, colnr_T col, proftime_T *tm, int *timed_out);
long vim_regexec_multi(regmmatch_T *rmp, win_T *win, buf_T *buf, linenr_T lnum, colnr_T col, int *timed_out);
/* vim: set ft=c : */