Remove who(1) from sbase
It now lives in ubase.
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parent
efbce07f94
commit
386aa62b94
1
Makefile
1
Makefile
@ -95,7 +95,6 @@ SRC = \
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sha256sum.c\
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sha512sum.c\
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wc.c \
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who.c \
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xargs.c \
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yes.c
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28
who.1
28
who.1
@ -1,28 +0,0 @@
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.TH WHO 1 sbase\-VERSION
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.SH NAME
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who \- print who has logged on
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.SH SYNOPSIS
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.B who
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.RB [ -m ]
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.SH DESCRIPTION
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.B who
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prints a list of who has logged on, their controlling tty, and the
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time at which they logged on.
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.SH OPTIONS
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.TP
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.B \-m
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only show users on current tty
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.TP
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.B \-l
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also print LOGIN processes
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.SH BUGS
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.B who
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relies on the utmp file to be updated responsibly. This
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doesn't always happen, which can cause who to print completely
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bogus data.
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.SH SEE ALSO
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.IR utmp (5)
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63
who.c
63
who.c
@ -1,63 +0,0 @@
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/* See LICENSE file for copyright and license details. */
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#include <stdio.h>
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#include <stdlib.h>
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#include <string.h>
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#include <unistd.h>
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#include <time.h>
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#include <utmp.h>
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#include "util.h"
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static void
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usage(void)
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{
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eprintf("usage: who [-ml]\n");
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}
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int
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main(int argc, char **argv)
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{
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struct utmp usr;
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FILE *ufp;
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char timebuf[sizeof "yyyy-mm-dd hh:mm"];
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char *tty, *ttmp;
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int mflag = 0, lflag = 0;
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time_t t;
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ARGBEGIN {
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case 'm':
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mflag = 1;
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tty = ttyname(STDIN_FILENO);
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if (!tty)
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eprintf("who: stdin:");
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if ((ttmp = strrchr(tty, '/')))
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tty = ttmp+1;
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break;
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case 'l':
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lflag = 1;
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break;
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default:
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usage();
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} ARGEND;
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if (argc > 0)
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usage();
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if (!(ufp = fopen("/var/run/utmp", "r")))
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eprintf("who: '%s':", "/var/run/utmp");
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while(fread(&usr, sizeof(usr), 1, ufp) == 1) {
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if (!*usr.ut_name || !*usr.ut_line ||
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usr.ut_line[0] == '~')
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continue;
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if (mflag && strcmp(usr.ut_line, tty))
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continue;
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if (strcmp(usr.ut_name, "LOGIN") == lflag)
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continue;
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t = usr.ut_time;
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strftime(timebuf, sizeof timebuf, "%Y-%m-%d %H:%M", localtime(&t));
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printf("%-8s %-12s %-16s\n", usr.ut_name, usr.ut_line, timebuf);
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}
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fclose(ufp);
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return EXIT_SUCCESS;
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}
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