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patch 8.2.4534: Vim9: "is" operator with empty string and null returns true

Problem:    Vim9: "is" operator with empty string and null returns true.
Solution:   Consider empty string and null to be different for "is".
This commit is contained in:
Bram Moolenaar
2022-03-10 12:20:53 +00:00
parent 56b84b1728
commit f8691004b0
4 changed files with 27 additions and 5 deletions

View File

@@ -801,6 +801,13 @@ def Test_expr4_compare_null()
assert_false(null_string != null)
assert_false(v:null != test_null_string())
assert_false(null != null_string)
assert_true(null_string is test_null_string())
assert_false(null_string is '')
assert_false('' is null_string)
assert_false(null_string isnot test_null_string())
assert_true(null_string isnot '')
assert_true('' isnot null_string)
END
v9.CheckDefAndScriptSuccess(lines)
unlet g:null_dict

View File

@@ -1583,9 +1583,23 @@ typval_compare_string(
i = ic ? MB_STRICMP(s1, s2) : STRCMP(s1, s2);
switch (type)
{
case EXPR_IS:
case EXPR_IS: if (in_vim9script())
{
// Really check it is the same string, not just
// the same value.
val = tv1->vval.v_string == tv2->vval.v_string;
break;
}
// FALLTHROUGH
case EXPR_EQUAL: val = (i == 0); break;
case EXPR_ISNOT:
case EXPR_ISNOT: if (in_vim9script())
{
// Really check it is not the same string, not
// just a different value.
val = tv1->vval.v_string != tv2->vval.v_string;
break;
}
// FALLTHROUGH
case EXPR_NEQUAL: val = (i != 0); break;
case EXPR_GREATER: val = (i > 0); break;
case EXPR_GEQUAL: val = (i >= 0); break;

View File

@@ -750,6 +750,8 @@ static char *(features[]) =
static int included_patches[] =
{ /* Add new patch number below this line */
/**/
4534,
/**/
4533,
/**/

View File

@@ -3313,9 +3313,8 @@ exec_instructions(ectx_T *ectx)
break;
default:
tv->v_type = VAR_STRING;
tv->vval.v_string = vim_strsave(
iptr->isn_arg.string == NULL
? (char_u *)"" : iptr->isn_arg.string);
tv->vval.v_string = iptr->isn_arg.string == NULL
? NULL : vim_strsave(iptr->isn_arg.string);
}
break;